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3x^2=3072
We move all terms to the left:
3x^2-(3072)=0
a = 3; b = 0; c = -3072;
Δ = b2-4ac
Δ = 02-4·3·(-3072)
Δ = 36864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36864}=192$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-192}{2*3}=\frac{-192}{6} =-32 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+192}{2*3}=\frac{192}{6} =32 $
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